(c^2+8c+19)=0

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Solution for (c^2+8c+19)=0 equation:


Simplifying
(c2 + 8c + 19) = 0

Reorder the terms:
(19 + 8c + c2) = 0

Remove parenthesis around (19 + 8c + c2)
19 + 8c + c2 = 0

Solving
19 + 8c + c2 = 0

Solving for variable 'c'.

Begin completing the square.

Move the constant term to the right:

Add '-19' to each side of the equation.
19 + 8c + -19 + c2 = 0 + -19

Reorder the terms:
19 + -19 + 8c + c2 = 0 + -19

Combine like terms: 19 + -19 = 0
0 + 8c + c2 = 0 + -19
8c + c2 = 0 + -19

Combine like terms: 0 + -19 = -19
8c + c2 = -19

The c term is 8c.  Take half its coefficient (4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
8c + 16 + c2 = -19 + 16

Reorder the terms:
16 + 8c + c2 = -19 + 16

Combine like terms: -19 + 16 = -3
16 + 8c + c2 = -3

Factor a perfect square on the left side:
(c + 4)(c + 4) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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